展開1

1. 次の式を展開せよ。

① a(x+2)② x(x-3)③ -x(x-5)

④ (4x2+12)÷2⑤ (3x2-9x+12)÷3

2. 次の式を展開せよ。

① (x+2)(x+5)② (x+3)(x-1)

③ (x+9)(x+11)④ (x-4)(x+3)

⑤ (x-5)(x-7)⑥ (x+2)(x-12)

⑦ (x-1)(x-30)⑧ (x+3)(x-3)

⑨ (x+5)2⑩ (x-4)2

⑪ (x+y)2⑫ (x+y)(x-y)

1.

①ax+2a  ②x2-3x  ③-x2+5x  ④2x2+6  ⑤x2-3x+4

2.

①x2+7x+10  ②x2+2x-3  ③x2+20x+99  ④x2-x-12
⑤x2-12x+35  ⑥x2-10x-24  ⑦x2-31x+30  ⑧x2-9
⑨x2+10x+25  ⑩x2-8x+16  ⑪x2+2xy+y2  ⑫x2-y2